M J Bridge
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♣
Bidding
This page added 10th Nov 2017
On an unadjusted count, N/S have seventeen combined points and a nine-
E/W have twenty three points and an eight-
N/S would expect to make seven tricks in spades, losing one spade, two clubs, one heart and two diamonds.
E/W would expect to make ten tricks in hearts losing one spade, one heart, and one diamond.
Total trumps 9 + 8 = 17
Total tricks 7 + 10 = 17
Move the ♠K from the East hand to the West hand, and then N/S make eight tricks and E/W make nine tricks -
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N
A Q T 5 4
3 2
K 8 3
K J T
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♥
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♣
S
9 8 6 3
A T 7
9 7 6
9 7 4
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♥
♦
♣
W
J 7
K Q 8
A T 5 4 2
6 3 2
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E
K 2
J 9 6 5 4
Q J
A Q 8 5
Just to give an idea why this might work
Suppose that all four players at the table hold balanced hands:-
with the points dividing twenty -
of course, if a particular finesse works one pair might make eight tricks, but equally this trick will lose for the other pair and so they will score only six;
if there is a particularly poor trump split then you might make one less than anticipated, but when your opponents play the hand they will make an extra trick in your suit;
if you are lucky enough to be able to take a ruff in the hand with the short trump suit you might make an extra trick, but your opponents will either lose a trick to a ruff in this suit if it is a side-
if the points divide twenty three-
in all of these variations the total number of tricks available between the two sides is fourteen -
And if you have an eight-
For a fuller analytic treatment of ‘the law of total tricks’ follow this link.
Opener |
Overcaller |
Responder |
Advancer |
Opener's rebid |
Responder's rebid and beyond |
Overcaller's rebid and beyond |
The continuing auction |